Solve 4/5(5x-5)-1=2/3(9x+9)-13

$$\frac{ 4 }{ 5 } (5x-5)-1= \frac{ 2 }{ 3 } (9x+9)-13$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{4}{5} by 5x-5.

$$\frac{4}{5}\times 5x+\frac{4}{5}\left(-5\right)-1=\frac{2}{3}\left(9x+9\right)-13$$

Cancel out 5 and 5.

$$4x+\frac{4}{5}\left(-5\right)-1=\frac{2}{3}\left(9x+9\right)-13$$

Express \frac{4}{5}\left(-5\right) as a single fraction.

$$4x+\frac{4\left(-5\right)}{5}-1=\frac{2}{3}\left(9x+9\right)-13$$

Multiply 4 and -5 to get -20.

$$4x+\frac{-20}{5}-1=\frac{2}{3}\left(9x+9\right)-13$$

Divide -20 by 5 to get -4.

$$4x-4-1=\frac{2}{3}\left(9x+9\right)-13$$

Subtract 1 from -4 to get -5.

$$4x-5=\frac{2}{3}\left(9x+9\right)-13$$

Use the distributive property to multiply \frac{2}{3} by 9x+9.

$$4x-5=\frac{2}{3}\times 9x+\frac{2}{3}\times 9-13$$

Express \frac{2}{3}\times 9 as a single fraction.

$$4x-5=\frac{2\times 9}{3}x+\frac{2}{3}\times 9-13$$

Multiply 2 and 9 to get 18.

$$4x-5=\frac{18}{3}x+\frac{2}{3}\times 9-13$$

Divide 18 by 3 to get 6.

$$4x-5=6x+\frac{2}{3}\times 9-13$$

Express \frac{2}{3}\times 9 as a single fraction.

$$4x-5=6x+\frac{2\times 9}{3}-13$$

Multiply 2 and 9 to get 18.

$$4x-5=6x+\frac{18}{3}-13$$

Divide 18 by 3 to get 6.

$$4x-5=6x+6-13$$

Subtract 13 from 6 to get -7.

$$4x-5=6x-7$$

Subtract 6x from both sides.

$$4x-5-6x=-7$$

Combine 4x and -6x to get -2x.

$$-2x-5=-7$$

Add 5 to both sides.

$$-2x=-7+5$$

Add -7 and 5 to get -2.

$$-2x=-2$$

Divide both sides by -2.

$$x=\frac{-2}{-2}$$

Divide -2 by -2 to get 1.

$$x=1$$