Solve 4/3y=-4x-4

$$\frac{ 4 }{ 3 } y=-4x-4$$

Solve for x

$$x=-\frac{y}{3}-1$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-4x-4=\frac{4}{3}y$$

Add 4 to both sides.

$$-4x=\frac{4}{3}y+4$$

The equation is in standard form.

$$-4x=\frac{4y}{3}+4$$

Divide both sides by -4.

$$\frac{-4x}{-4}=\frac{\frac{4y}{3}+4}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$x=\frac{\frac{4y}{3}+4}{-4}$$

Divide 4+\frac{4y}{3} by -4.

$$x=-\frac{y}{3}-1$$

Solve for y

$$y=-3x-3$$

Steps for Solving Linear Equation

The equation is in standard form.

$$\frac{4}{3}y=-4x-4$$

Divide both sides of the equation by \frac{4}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{4}{3}y}{\frac{4}{3}}=\frac{-4x-4}{\frac{4}{3}}$$

Dividing by \frac{4}{3} undoes the multiplication by \frac{4}{3}.

$$y=\frac{-4x-4}{\frac{4}{3}}$$

Divide -4x-4 by \frac{4}{3} by multiplying -4x-4 by the reciprocal of \frac{4}{3}.

$$y=-3x-3$$