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\frac{4}{3}x-\frac{3}{4}-\frac{2}{3}x=-\frac{1}{4}
Subtract \frac{2}{3}x from both sides.
\frac{2}{3}x-\frac{3}{4}=-\frac{1}{4}
Combine \frac{4}{3}x and -\frac{2}{3}x to get \frac{2}{3}x.
\frac{2}{3}x=-\frac{1}{4}+\frac{3}{4}
Add \frac{3}{4} to both sides.
\frac{2}{3}x=\frac{-1+3}{4}
Since -\frac{1}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.
\frac{2}{3}x=\frac{2}{4}
Add -1 and 3 to get 2.
\frac{2}{3}x=\frac{1}{2}
Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.
x=\frac{1}{2}\times \frac{3}{2}
Multiply both sides by \frac{3}{2}, the reciprocal of \frac{2}{3}.
x=\frac{1\times 3}{2\times 2}
Multiply \frac{1}{2} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.
x=\frac{3}{4}
Do the multiplications in the fraction \frac{1\times 3}{2\times 2}.