Solve 4/3-2/981-16/243

$$\frac{ 4 }{ 3 } - \frac{ 2 }{ 9 } 81- \frac{ 16 }{ 243 }$$

Evaluate

$$-\frac{4066}{243}\approx -16.732510288$$

Solution Steps

Express \frac{2}{9}\times 81 as a single fraction.

$$\frac{4}{3}-\frac{2\times 81}{9}-\frac{16}{243}$$

Multiply 2 and 81 to get 162.

$$\frac{4}{3}-\frac{162}{9}-\frac{16}{243}$$

Divide 162 by 9 to get 18.

$$\frac{4}{3}-18-\frac{16}{243}$$

Convert 18 to fraction \frac{54}{3}.

$$\frac{4}{3}-\frac{54}{3}-\frac{16}{243}$$

Since \frac{4}{3} and \frac{54}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-54}{3}-\frac{16}{243}$$

Subtract 54 from 4 to get -50.

$$-\frac{50}{3}-\frac{16}{243}$$

Least common multiple of 3 and 243 is 243. Convert -\frac{50}{3} and \frac{16}{243} to fractions with denominator 243.

$$-\frac{4050}{243}-\frac{16}{243}$$

Since -\frac{4050}{243} and \frac{16}{243} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-4050-16}{243}$$

Subtract 16 from -4050 to get -4066.

$$-\frac{4066}{243}$$

Factor

$$-\frac{4066}{243} = -16\frac{178}{243} = -16.732510288065843$$