Solve 4/3+(3/2-4/3=

$$\frac{ 4 }{ 3 } +( \frac{ 3 }{ 2 } - \frac{ 4 }{ 3 } =$$

Evaluate

$$\frac{3}{2}=1.5$$

Solution Steps

Least common multiple of 3 and 2 is 6. Convert \frac{4}{3} and \frac{3}{2} to fractions with denominator 6.

$$\frac{8}{6}+\frac{9}{6}-\frac{4}{3}$$

Since \frac{8}{6} and \frac{9}{6} have the same denominator, add them by adding their numerators.

$$\frac{8+9}{6}-\frac{4}{3}$$

Add 8 and 9 to get 17.

$$\frac{17}{6}-\frac{4}{3}$$

Least common multiple of 6 and 3 is 6. Convert \frac{17}{6} and \frac{4}{3} to fractions with denominator 6.

$$\frac{17}{6}-\frac{8}{6}$$

Since \frac{17}{6} and \frac{8}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{17-8}{6}$$

Subtract 8 from 17 to get 9.

$$\frac{9}{6}$$

Reduce the fraction \frac{9}{6} to lowest terms by extracting and canceling out 3.

$$\frac{3}{2}$$

Factor

$$\frac{3}{2} = 1\frac{1}{2} = 1.5$$