Solve 4/3left(4*2right)^3=6^2*x

$$\frac{ 4 }{ 3 } { \left(4 \cdot 2 \right) }^{ 3 } = { 6 }^{ 2 } \times x$$

Solve for x

$$x = \frac{512}{27} = 18\frac{26}{27} \approx 18.962962963$$

Steps for Solving Linear Equation

Multiply 4 and 2 to get 8.

$$\frac{4}{3}\times 8^{3}=6^{2}x$$

Calculate 8 to the power of 3 and get 512.

$$\frac{4}{3}\times 512=6^{2}x$$

Multiply \frac{4}{3} and 512 to get \frac{2048}{3}.

$$\frac{2048}{3}=6^{2}x$$

Calculate 6 to the power of 2 and get 36.

$$\frac{2048}{3}=36x$$

Swap sides so that all variable terms are on the left hand side.

$$36x=\frac{2048}{3}$$

Divide both sides by 36.

$$x=\frac{\frac{2048}{3}}{36}$$

Express \frac{\frac{2048}{3}}{36} as a single fraction.

$$x=\frac{2048}{3\times 36}$$

Multiply 3 and 36 to get 108.

$$x=\frac{2048}{108}$$

Reduce the fraction \frac{2048}{108} to lowest terms by extracting and canceling out 4.

$$x=\frac{512}{27}$$