Solve 4/0+2+1/0-2=5(0)-6/0^2-4

$$\frac{ 4 }{ 0+2 } + \frac{ 1 }{ 0-2 } = \frac{ 5(0)-6 }{ { 0 }^{ 2 } -4 }$$

Verify

Solution Steps

Add 0 and 2 to get 2.

$$\frac{4}{2}+\frac{1}{0-2}=\frac{5\times 0-6}{0^{2}-4}$$

Divide 4 by 2 to get 2.

$$2+\frac{1}{0-2}=\frac{5\times 0-6}{0^{2}-4}$$

Subtract 2 from 0 to get -2.

$$2+\frac{1}{-2}=\frac{5\times 0-6}{0^{2}-4}$$

Fraction \frac{1}{-2} can be rewritten as -\frac{1}{2} by extracting the negative sign.

$$2-\frac{1}{2}=\frac{5\times 0-6}{0^{2}-4}$$

Convert 2 to fraction \frac{4}{2}.

$$\frac{4}{2}-\frac{1}{2}=\frac{5\times 0-6}{0^{2}-4}$$

Since \frac{4}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-1}{2}=\frac{5\times 0-6}{0^{2}-4}$$

Subtract 1 from 4 to get 3.

$$\frac{3}{2}=\frac{5\times 0-6}{0^{2}-4}$$

Multiply 5 and 0 to get 0.

$$\frac{3}{2}=\frac{0-6}{0^{2}-4}$$

Subtract 6 from 0 to get -6.

$$\frac{3}{2}=\frac{-6}{0^{2}-4}$$

Calculate 0 to the power of 2 and get 0.

$$\frac{3}{2}=\frac{-6}{0-4}$$

Subtract 4 from 0 to get -4.

$$\frac{3}{2}=\frac{-6}{-4}$$

Reduce the fraction \frac{-6}{-4} to lowest terms by extracting and canceling out -2.

$$\frac{3}{2}=\frac{3}{2}$$

Compare \frac{3}{2} and \frac{3}{2}.

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