Solve 4/4^3*(3/4)

$$\frac{ 4 }{ { 4 }^{ 3 } } \times ( \frac{ 3 }{ 4 } )$$

Evaluate

$$\frac{3}{64}=0.046875$$

Solution Steps

Rewrite 4^{3} as 4\times 4^{2}. Cancel out 4 in both numerator and denominator.

$$\frac{1}{4^{2}}\times \frac{3}{4}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{1}{16}\times \frac{3}{4}$$

Multiply \frac{1}{16} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 3}{16\times 4}$$

Do the multiplications in the fraction \frac{1\times 3}{16\times 4}.

$$\frac{3}{64}$$

Factor

$$\frac{3}{2 ^ {6}} = 0.046875$$