Solve 4!/3!(4-3)!*6!/1!(6-1)!

$$\frac{ 4 ! }{ 3 ! (4-3) ! } \times \frac{ 6 ! }{ 1 ! (6-1) ! }$$

Evaluate

$$24$$

Solution Steps

The factorial of 4 is 24.

$$\frac{24}{3!\left(4-3\right)!}\times \frac{6!}{1!\left(6-1\right)!}$$

The factorial of 3 is 6.

$$\frac{24}{6\left(4-3\right)!}\times \frac{6!}{1!\left(6-1\right)!}$$

Subtract 3 from 4 to get 1.

$$\frac{24}{6\times 1!}\times \frac{6!}{1!\left(6-1\right)!}$$

The factorial of 1 is 1.

$$\frac{24}{6\times 1}\times \frac{6!}{1!\left(6-1\right)!}$$

Multiply 6 and 1 to get 6.

$$\frac{24}{6}\times \frac{6!}{1!\left(6-1\right)!}$$

Divide 24 by 6 to get 4.

$$4\times \frac{6!}{1!\left(6-1\right)!}$$

The factorial of 6 is 720.

$$4\times \frac{720}{1!\left(6-1\right)!}$$

The factorial of 1 is 1.

$$4\times \frac{720}{1\left(6-1\right)!}$$

Subtract 1 from 6 to get 5.

$$4\times \frac{720}{1\times 5!}$$

The factorial of 5 is 120.

$$4\times \frac{720}{1\times 120}$$

Multiply 1 and 120 to get 120.

$$4\times \frac{720}{120}$$

Divide 720 by 120 to get 6.

$$4\times 6$$

Multiply 4 and 6 to get 24.

$$24$$

Factor

$$2^{3}\times 3$$