Solve 4!/(4-2)!2!*left(.6right)^2*1.4^(4-2)

$$\frac{ 4 ! }{ (4-2) ! 2 ! } \times { \left(.6 \right) }^{ 2 } \times { 1.4 }^{ (4-2) }$$

Evaluate

$$4.2336$$

Solution Steps

The factorial of 4 is 24.

$$\frac{24}{\left(4-2\right)!\times 2!}\times 0.6^{2}\times 1.4^{4-2}$$

Subtract 2 from 4 to get 2.

$$\frac{24}{2!\times 2!}\times 0.6^{2}\times 1.4^{4-2}$$

The factorial of 2 is 2.

$$\frac{24}{2\times 2!}\times 0.6^{2}\times 1.4^{4-2}$$

The factorial of 2 is 2.

$$\frac{24}{2\times 2}\times 0.6^{2}\times 1.4^{4-2}$$

Multiply 2 and 2 to get 4.

$$\frac{24}{4}\times 0.6^{2}\times 1.4^{4-2}$$

Divide 24 by 4 to get 6.

$$6\times 0.6^{2}\times 1.4^{4-2}$$

Calculate 0.6 to the power of 2 and get 0.36.

$$6\times 0.36\times 1.4^{4-2}$$

Multiply 6 and 0.36 to get 2.16.

$$2.16\times 1.4^{4-2}$$

Subtract 2 from 4 to get 2.

$$2.16\times 1.4^{2}$$

Calculate 1.4 to the power of 2 and get 1.96.

$$2.16\times 1.96$$

Multiply 2.16 and 1.96 to get 4.2336.

$$4.2336$$

Factor

$$\frac{2 \cdot 3 ^ {3} \cdot 7 ^ {2}}{5 ^ {4}} = 4\frac{146}{625} = 4.2336$$