Solve for x
x=-\frac{1}{4}=-0.25
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\left(2x-3\right)\left(3x+1\right)=\left(3x-1\right)\left(2x+1\right)
Variable x cannot be equal to any of the values \frac{1}{3},\frac{3}{2} since division by zero is not defined. Multiply both sides of the equation by \left(2x-3\right)\left(3x-1\right), the least common multiple of 3x-1,2x-3.
6x^{2}-7x-3=\left(3x-1\right)\left(2x+1\right)
Use the distributive property to multiply 2x-3 by 3x+1 and combine like terms.
6x^{2}-7x-3=6x^{2}+x-1
Use the distributive property to multiply 3x-1 by 2x+1 and combine like terms.
6x^{2}-7x-3-6x^{2}=x-1
Subtract 6x^{2} from both sides.
-7x-3=x-1
Combine 6x^{2} and -6x^{2} to get 0.
-7x-3-x=-1
Subtract x from both sides.
-8x-3=-1
Combine -7x and -x to get -8x.
-8x=-1+3
Add 3 to both sides.
-8x=2
Add -1 and 3 to get 2.
x=\frac{2}{-8}
Divide both sides by -8.
x=-\frac{1}{4}
Reduce the fraction \frac{2}{-8} to lowest terms by extracting and canceling out 2.
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