Solve 3x/4-x-2/4=x

$$\frac{ 3x }{ 4 } - \frac{ x-2 }{ 4 } =x$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Since \frac{3x}{4} and \frac{x-2}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3x-\left(x-2\right)}{4}=x$$

Do the multiplications in 3x-\left(x-2\right).

$$\frac{3x-x+2}{4}=x$$

Combine like terms in 3x-x+2.

$$\frac{2x+2}{4}=x$$

Divide each term of 2x+2 by 4 to get \frac{1}{2}x+\frac{1}{2}.

$$\frac{1}{2}x+\frac{1}{2}=x$$

Subtract x from both sides.

$$\frac{1}{2}x+\frac{1}{2}-x=0$$

Combine \frac{1}{2}x and -x to get -\frac{1}{2}x.

$$-\frac{1}{2}x+\frac{1}{2}=0$$

Subtract \frac{1}{2} from both sides. Anything subtracted from zero gives its negation.

$$-\frac{1}{2}x=-\frac{1}{2}$$

Multiply both sides by -2, the reciprocal of -\frac{1}{2}.

$$x=-\frac{1}{2}\left(-2\right)$$

Express -\frac{1}{2}\left(-2\right) as a single fraction.

$$x=\frac{-\left(-2\right)}{2}$$

Multiply -1 and -2 to get 2.

$$x=\frac{2}{2}$$

Divide 2 by 2 to get 1.

$$x=1$$