Solve for x
x = \frac{50000 \sqrt{4422}}{67} \approx 49625.462891183
x = -\frac{50000 \sqrt{4422}}{67} \approx -49625.462891183
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3960000000=1.608xx
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
3960000000=1.608x^{2}
Multiply x and x to get x^{2}.
1.608x^{2}=3960000000
Swap sides so that all variable terms are on the left hand side.
x^{2}=\frac{3960000000}{1.608}
Divide both sides by 1.608.
x^{2}=\frac{3960000000000}{1608}
Expand \frac{3960000000}{1.608} by multiplying both numerator and the denominator by 1000.
x^{2}=\frac{165000000000}{67}
Reduce the fraction \frac{3960000000000}{1608} to lowest terms by extracting and canceling out 24.
x=\frac{50000\sqrt{4422}}{67} x=-\frac{50000\sqrt{4422}}{67}
Take the square root of both sides of the equation.
3960000000=1.608xx
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
3960000000=1.608x^{2}
Multiply x and x to get x^{2}.
1.608x^{2}=3960000000
Swap sides so that all variable terms are on the left hand side.
1.608x^{2}-3960000000=0
Subtract 3960000000 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times 1.608\left(-3960000000\right)}}{2\times 1.608}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1.608 for a, 0 for b, and -3960000000 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 1.608\left(-3960000000\right)}}{2\times 1.608}
Square 0.
x=\frac{0±\sqrt{-6.432\left(-3960000000\right)}}{2\times 1.608}
Multiply -4 times 1.608.
x=\frac{0±\sqrt{25470720000}}{2\times 1.608}
Multiply -6.432 times -3960000000.
x=\frac{0±2400\sqrt{4422}}{2\times 1.608}
Take the square root of 25470720000.
x=\frac{0±2400\sqrt{4422}}{3.216}
Multiply 2 times 1.608.
x=\frac{50000\sqrt{4422}}{67}
Now solve the equation x=\frac{0±2400\sqrt{4422}}{3.216} when ± is plus.
x=-\frac{50000\sqrt{4422}}{67}
Now solve the equation x=\frac{0±2400\sqrt{4422}}{3.216} when ± is minus.
x=\frac{50000\sqrt{4422}}{67} x=-\frac{50000\sqrt{4422}}{67}
The equation is now solved.
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