Solve 35/16=x^2

$$\frac{ 35 }{ 16 } = { x }^{ 2 }$$

Solve for x

$$x = \frac{\sqrt{35}}{4} \approx 1.479019946$$

$$x = -\frac{\sqrt{35}}{4} \approx -1.479019946$$

Steps by Finding Square Root

Swap sides so that all variable terms are on the left hand side.

$$x^{2}=\frac{35}{16}$$

Take the square root of both sides of the equation.

$$x=\frac{\sqrt{35}}{4} x=-\frac{\sqrt{35}}{4}$$

Steps Using the Quadratic Formula

Swap sides so that all variable terms are on the left hand side.

$$x^{2}=\frac{35}{16}$$

Subtract \frac{35}{16} from both sides.

$$x^{2}-\frac{35}{16}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{35}{16} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-\frac{35}{16}\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-\frac{35}{16}\right)}}{2}$$

Multiply -4 times -\frac{35}{16}.

$$x=\frac{0±\sqrt{\frac{35}{4}}}{2}$$

Take the square root of \frac{35}{4}.

$$x=\frac{0±\frac{\sqrt{35}}{2}}{2}$$

Now solve the equation x=\frac{0±\frac{\sqrt{35}}{2}}{2} when ± is plus.

$$x=\frac{\sqrt{35}}{4}$$

Now solve the equation x=\frac{0±\frac{\sqrt{35}}{2}}{2} when ± is minus.

$$x=-\frac{\sqrt{35}}{4}$$

The equation is now solved.

$$x=\frac{\sqrt{35}}{4} x=-\frac{\sqrt{35}}{4}$$