Solve 340left(3-21/17right)/120left(5+frac{1{3}right)}

$$\frac{ 340 \left( 3-2 \frac{ 1 }{ 17 } \right) }{ 120 \left( 5+ \frac{ 1 }{ 3 } \right) }$$

Evaluate

$$\frac{1}{2}=0.5$$

Solution Steps

Multiply 2 and 17 to get 34.

$$\frac{340\left(3-\frac{34+1}{17}\right)}{120\left(5+\frac{1}{3}\right)}$$

Add 34 and 1 to get 35.

$$\frac{340\left(3-\frac{35}{17}\right)}{120\left(5+\frac{1}{3}\right)}$$

Convert 3 to fraction \frac{51}{17}.

$$\frac{340\left(\frac{51}{17}-\frac{35}{17}\right)}{120\left(5+\frac{1}{3}\right)}$$

Since \frac{51}{17} and \frac{35}{17} have the same denominator, subtract them by subtracting their numerators.

$$\frac{340\times \frac{51-35}{17}}{120\left(5+\frac{1}{3}\right)}$$

Subtract 35 from 51 to get 16.

$$\frac{340\times \frac{16}{17}}{120\left(5+\frac{1}{3}\right)}$$

Express 340\times \frac{16}{17} as a single fraction.

$$\frac{\frac{340\times 16}{17}}{120\left(5+\frac{1}{3}\right)}$$

Multiply 340 and 16 to get 5440.

$$\frac{\frac{5440}{17}}{120\left(5+\frac{1}{3}\right)}$$

Divide 5440 by 17 to get 320.

$$\frac{320}{120\left(5+\frac{1}{3}\right)}$$

Convert 5 to fraction \frac{15}{3}.

$$\frac{320}{120\left(\frac{15}{3}+\frac{1}{3}\right)}$$

Since \frac{15}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{320}{120\times \frac{15+1}{3}}$$

Add 15 and 1 to get 16.

$$\frac{320}{120\times \frac{16}{3}}$$

Express 120\times \frac{16}{3} as a single fraction.

$$\frac{320}{\frac{120\times 16}{3}}$$

Multiply 120 and 16 to get 1920.

$$\frac{320}{\frac{1920}{3}}$$

Divide 1920 by 3 to get 640.

$$\frac{320}{640}$$

Reduce the fraction \frac{320}{640} to lowest terms by extracting and canceling out 320.

$$\frac{1}{2}$$

Factor

$$\frac{1}{2} = 0.5$$