Solve 31/103/10+7/5div20

$$\frac{ 31 }{ 10 } \frac{ 3 }{ 10 } + \frac{ 7 }{ 5 } \div 20$$

Evaluate

$$1$$

Solution Steps

Multiply \frac{31}{10} times \frac{3}{10} by multiplying numerator times numerator and denominator times denominator.

$$\frac{31\times 3}{10\times 10}+\frac{\frac{7}{5}}{20}$$

Do the multiplications in the fraction \frac{31\times 3}{10\times 10}.

$$\frac{93}{100}+\frac{\frac{7}{5}}{20}$$

Express \frac{\frac{7}{5}}{20} as a single fraction.

$$\frac{93}{100}+\frac{7}{5\times 20}$$

Multiply 5 and 20 to get 100.

$$\frac{93}{100}+\frac{7}{100}$$

Since \frac{93}{100} and \frac{7}{100} have the same denominator, add them by adding their numerators.

$$\frac{93+7}{100}$$

Add 93 and 7 to get 100.

$$\frac{100}{100}$$

Divide 100 by 100 to get 1.

$$1$$

Factor

$$1$$