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30-6y+y^{2}=0
Variable y cannot be equal to any of the values 0,5 since division by zero is not defined. Multiply both sides of the equation by 6y\left(-y+5\right).
y^{2}-6y+30=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
y=\frac{-\left(-6\right)±\sqrt{\left(-6\right)^{2}-4\times 30}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -6 for b, and 30 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
y=\frac{-\left(-6\right)±\sqrt{36-4\times 30}}{2}
Square -6.
y=\frac{-\left(-6\right)±\sqrt{36-120}}{2}
Multiply -4 times 30.
y=\frac{-\left(-6\right)±\sqrt{-84}}{2}
Add 36 to -120.
y=\frac{-\left(-6\right)±2\sqrt{21}i}{2}
Take the square root of -84.
y=\frac{6±2\sqrt{21}i}{2}
The opposite of -6 is 6.
y=\frac{6+2\sqrt{21}i}{2}
Now solve the equation y=\frac{6±2\sqrt{21}i}{2} when ± is plus. Add 6 to 2i\sqrt{21}.
y=3+\sqrt{21}i
Divide 6+2i\sqrt{21} by 2.
y=\frac{-2\sqrt{21}i+6}{2}
Now solve the equation y=\frac{6±2\sqrt{21}i}{2} when ± is minus. Subtract 2i\sqrt{21} from 6.
y=-\sqrt{21}i+3
Divide 6-2i\sqrt{21} by 2.
y=3+\sqrt{21}i y=-\sqrt{21}i+3
The equation is now solved.
30-6y+y^{2}=0
Variable y cannot be equal to any of the values 0,5 since division by zero is not defined. Multiply both sides of the equation by 6y\left(-y+5\right).
-6y+y^{2}=-30
Subtract 30 from both sides. Anything subtracted from zero gives its negation.
y^{2}-6y=-30
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
y^{2}-6y+\left(-3\right)^{2}=-30+\left(-3\right)^{2}
Divide -6, the coefficient of the x term, by 2 to get -3. Then add the square of -3 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
y^{2}-6y+9=-30+9
Square -3.
y^{2}-6y+9=-21
Add -30 to 9.
\left(y-3\right)^{2}=-21
Factor y^{2}-6y+9. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(y-3\right)^{2}}=\sqrt{-21}
Take the square root of both sides of the equation.
y-3=\sqrt{21}i y-3=-\sqrt{21}i
Simplify.
y=3+\sqrt{21}i y=-\sqrt{21}i+3
Add 3 to both sides of the equation.