Solve 30-1/30-10=25-x/25-(-5)

$$\frac{ 30-1 }{ 30-10 } = \frac{ 25-x }{ 25-(-5) }$$

Solve for x

$$x = -\frac{37}{2} = -18\frac{1}{2} = -18.5$$

Steps for Solving Linear Equation

Subtract 1 from 30 to get 29.

$$\frac{29}{30-10}=\frac{25-x}{25-\left(-5\right)}$$

Subtract 10 from 30 to get 20.

$$\frac{29}{20}=\frac{25-x}{25-\left(-5\right)}$$

The opposite of -5 is 5.

$$\frac{29}{20}=\frac{25-x}{25+5}$$

Add 25 and 5 to get 30.

$$\frac{29}{20}=\frac{25-x}{30}$$

Divide each term of 25-x by 30 to get \frac{5}{6}-\frac{1}{30}x.

$$\frac{29}{20}=\frac{5}{6}-\frac{1}{30}x$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{5}{6}-\frac{1}{30}x=\frac{29}{20}$$

Subtract \frac{5}{6} from both sides.

$$-\frac{1}{30}x=\frac{29}{20}-\frac{5}{6}$$

Least common multiple of 20 and 6 is 60. Convert \frac{29}{20} and \frac{5}{6} to fractions with denominator 60.

$$-\frac{1}{30}x=\frac{87}{60}-\frac{50}{60}$$

Since \frac{87}{60} and \frac{50}{60} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{1}{30}x=\frac{87-50}{60}$$

Subtract 50 from 87 to get 37.

$$-\frac{1}{30}x=\frac{37}{60}$$

Multiply both sides by -30, the reciprocal of -\frac{1}{30}.

$$x=\frac{37}{60}\left(-30\right)$$

Express \frac{37}{60}\left(-30\right) as a single fraction.

$$x=\frac{37\left(-30\right)}{60}$$

Multiply 37 and -30 to get -1110.

$$x=\frac{-1110}{60}$$

Reduce the fraction \frac{-1110}{60} to lowest terms by extracting and canceling out 30.

$$x=-\frac{37}{2}$$