Solve 3.9-4/3.9^2-3(3.9)-4

$$\frac{ 3.9-4 }{ { 3.9 }^{ 2 } -3(3.9)-4 }$$

Evaluate

$$\frac{10}{49}\approx 0.204081633$$

Solution Steps

Subtract 4 from 3.9 to get -0.1.

$$\frac{-0.1}{3.9^{2}-3\times 3.9-4}$$

Calculate 3.9 to the power of 2 and get 15.21.

$$\frac{-0.1}{15.21-3\times 3.9-4}$$

Multiply 3 and 3.9 to get 11.7.

$$\frac{-0.1}{15.21-11.7-4}$$

Subtract 11.7 from 15.21 to get 3.51.

$$\frac{-0.1}{3.51-4}$$

Subtract 4 from 3.51 to get -0.49.

$$\frac{-0.1}{-0.49}$$

Expand \frac{-0.1}{-0.49} by multiplying both numerator and the denominator by 100.

$$\frac{-10}{-49}$$

Fraction \frac{-10}{-49} can be simplified to \frac{10}{49} by removing the negative sign from both the numerator and the denominator.

$$\frac{10}{49}$$

Factor

$$\frac{2 \cdot 5}{7 ^ {2}} = 0.20408163265306123$$