Solve 3(-5)/-5-1leq-5/-5+4+3

$$\frac{ 3(-5) }{ -5-1 } \leq \frac{ -5 }{ -5+4 } +3$$

Verify

Solution Steps

Multiply 3 and -5 to get -15.

$$\frac{-15}{-5-1}\leq \frac{-5}{-5+4}+3$$

Subtract 1 from -5 to get -6.

$$\frac{-15}{-6}\leq \frac{-5}{-5+4}+3$$

Reduce the fraction \frac{-15}{-6} to lowest terms by extracting and canceling out -3.

$$\frac{5}{2}\leq \frac{-5}{-5+4}+3$$

Add -5 and 4 to get -1.

$$\frac{5}{2}\leq \frac{-5}{-1}+3$$

Fraction \frac{-5}{-1} can be simplified to 5 by removing the negative sign from both the numerator and the denominator.

$$\frac{5}{2}\leq 5+3$$

Add 5 and 3 to get 8.

$$\frac{5}{2}\leq 8$$

Convert 8 to fraction \frac{16}{2}.

$$\frac{5}{2}\leq \frac{16}{2}$$

Compare \frac{5}{2} and \frac{16}{2}.

$$\text{true}$$