Solve 3y^2+3yh+3yh+3h^2-4yh-(3y^2-4y)/y+h-y

$$\frac{ 3 { y }^{ 2 } +3yh+3yh+3 { h }^{ 2 } -4yh-(3 { y }^{ 2 } -4y) }{ y+h-y }$$

Evaluate

$$2y+3h+\frac{4y}{h}$$

Solution Steps

Combine 3yh and 3yh to get 6yh.

$$\frac{3y^{2}+6yh+3h^{2}-4yh-\left(3y^{2}-4y\right)}{y+h-y}$$

Combine 6yh and -4yh to get 2yh.

$$\frac{3y^{2}+2yh+3h^{2}-\left(3y^{2}-4y\right)}{y+h-y}$$

Combine y and -y to get 0.

$$\frac{3y^{2}+2yh+3h^{2}-\left(3y^{2}-4y\right)}{h}$$

To find the opposite of 3y^{2}-4y, find the opposite of each term.

$$\frac{3y^{2}+2yh+3h^{2}-3y^{2}+4y}{h}$$

Combine 3y^{2} and -3y^{2} to get 0.

$$\frac{2yh+3h^{2}+4y}{h}$$

Expand

$$2y+3h+\frac{4y}{h}$$

Solution Steps

Combine 3yh and 3yh to get 6yh.

$$\frac{3y^{2}+6yh+3h^{2}-4yh-\left(3y^{2}-4y\right)}{y+h-y}$$

Combine 6yh and -4yh to get 2yh.

$$\frac{3y^{2}+2yh+3h^{2}-\left(3y^{2}-4y\right)}{y+h-y}$$

Combine y and -y to get 0.

$$\frac{3y^{2}+2yh+3h^{2}-\left(3y^{2}-4y\right)}{h}$$

To find the opposite of 3y^{2}-4y, find the opposite of each term.

$$\frac{3y^{2}+2yh+3h^{2}-3y^{2}+4y}{h}$$

Combine 3y^{2} and -3y^{2} to get 0.

$$\frac{2yh+3h^{2}+4y}{h}$$