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\frac{x^{2}-9}{3}
Factor out \frac{1}{3}.
\left(x-3\right)\left(x+3\right)
Consider x^{2}-9. Rewrite x^{2}-9 as x^{2}-3^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{\left(x-3\right)\left(x+3\right)}{3}
Rewrite the complete factored expression.
\frac{1}{3}x^{2}-3
Divide 3x^{2} by 9 to get \frac{1}{3}x^{2}.