Solve 3*1/4-1/2*frac{1{4}+1}

$$\frac{ 3 \times \frac{ 1 }{ 4 } -1 }{ 2 \times \frac{ 1 }{ 4 } +1 }$$

Evaluate

$$-\frac{1}{6}\approx -0.166666667$$

Solution Steps

Multiply 3 and \frac{1}{4} to get \frac{3}{4}.

$$\frac{\frac{3}{4}-1}{2\times \frac{1}{4}+1}$$

Convert 1 to fraction \frac{4}{4}.

$$\frac{\frac{3}{4}-\frac{4}{4}}{2\times \frac{1}{4}+1}$$

Since \frac{3}{4} and \frac{4}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{3-4}{4}}{2\times \frac{1}{4}+1}$$

Subtract 4 from 3 to get -1.

$$\frac{-\frac{1}{4}}{2\times \frac{1}{4}+1}$$

Multiply 2 and \frac{1}{4} to get \frac{2}{4}.

$$\frac{-\frac{1}{4}}{\frac{2}{4}+1}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{-\frac{1}{4}}{\frac{1}{2}+1}$$

Convert 1 to fraction \frac{2}{2}.

$$\frac{-\frac{1}{4}}{\frac{1}{2}+\frac{2}{2}}$$

Since \frac{1}{2} and \frac{2}{2} have the same denominator, add them by adding their numerators.

$$\frac{-\frac{1}{4}}{\frac{1+2}{2}}$$

Add 1 and 2 to get 3.

$$\frac{-\frac{1}{4}}{\frac{3}{2}}$$

Divide -\frac{1}{4} by \frac{3}{2} by multiplying -\frac{1}{4} by the reciprocal of \frac{3}{2}.

$$-\frac{1}{4}\times \frac{2}{3}$$

Multiply -\frac{1}{4} times \frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-2}{4\times 3}$$

Do the multiplications in the fraction \frac{-2}{4\times 3}.

$$\frac{-2}{12}$$

Reduce the fraction \frac{-2}{12} to lowest terms by extracting and canceling out 2.

$$-\frac{1}{6}$$

Factor

$$-\frac{1}{6} = -0.16666666666666666$$