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\frac{\left(3\sqrt{5}+\sqrt{15}\right)\left(2\sqrt{5}+\sqrt{15}\right)}{\left(2\sqrt{5}-\sqrt{15}\right)\left(2\sqrt{5}+\sqrt{15}\right)}
Rationalize the denominator of \frac{3\sqrt{5}+\sqrt{15}}{2\sqrt{5}-\sqrt{15}} by multiplying numerator and denominator by 2\sqrt{5}+\sqrt{15}.
\frac{\left(3\sqrt{5}+\sqrt{15}\right)\left(2\sqrt{5}+\sqrt{15}\right)}{\left(2\sqrt{5}\right)^{2}-\left(\sqrt{15}\right)^{2}}
Consider \left(2\sqrt{5}-\sqrt{15}\right)\left(2\sqrt{5}+\sqrt{15}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(3\sqrt{5}+\sqrt{15}\right)\left(2\sqrt{5}+\sqrt{15}\right)}{2^{2}\left(\sqrt{5}\right)^{2}-\left(\sqrt{15}\right)^{2}}
Expand \left(2\sqrt{5}\right)^{2}.
\frac{\left(3\sqrt{5}+\sqrt{15}\right)\left(2\sqrt{5}+\sqrt{15}\right)}{4\left(\sqrt{5}\right)^{2}-\left(\sqrt{15}\right)^{2}}
Calculate 2 to the power of 2 and get 4.
\frac{\left(3\sqrt{5}+\sqrt{15}\right)\left(2\sqrt{5}+\sqrt{15}\right)}{4\times 5-\left(\sqrt{15}\right)^{2}}
The square of \sqrt{5} is 5.
\frac{\left(3\sqrt{5}+\sqrt{15}\right)\left(2\sqrt{5}+\sqrt{15}\right)}{20-\left(\sqrt{15}\right)^{2}}
Multiply 4 and 5 to get 20.
\frac{\left(3\sqrt{5}+\sqrt{15}\right)\left(2\sqrt{5}+\sqrt{15}\right)}{20-15}
The square of \sqrt{15} is 15.
\frac{\left(3\sqrt{5}+\sqrt{15}\right)\left(2\sqrt{5}+\sqrt{15}\right)}{5}
Subtract 15 from 20 to get 5.
\frac{6\left(\sqrt{5}\right)^{2}+3\sqrt{5}\sqrt{15}+2\sqrt{15}\sqrt{5}+\left(\sqrt{15}\right)^{2}}{5}
Apply the distributive property by multiplying each term of 3\sqrt{5}+\sqrt{15} by each term of 2\sqrt{5}+\sqrt{15}.
\frac{6\times 5+3\sqrt{5}\sqrt{15}+2\sqrt{15}\sqrt{5}+\left(\sqrt{15}\right)^{2}}{5}
The square of \sqrt{5} is 5.
\frac{30+3\sqrt{5}\sqrt{15}+2\sqrt{15}\sqrt{5}+\left(\sqrt{15}\right)^{2}}{5}
Multiply 6 and 5 to get 30.
\frac{30+3\sqrt{5}\sqrt{5}\sqrt{3}+2\sqrt{15}\sqrt{5}+\left(\sqrt{15}\right)^{2}}{5}
Factor 15=5\times 3. Rewrite the square root of the product \sqrt{5\times 3} as the product of square roots \sqrt{5}\sqrt{3}.
\frac{30+3\times 5\sqrt{3}+2\sqrt{15}\sqrt{5}+\left(\sqrt{15}\right)^{2}}{5}
Multiply \sqrt{5} and \sqrt{5} to get 5.
\frac{30+15\sqrt{3}+2\sqrt{15}\sqrt{5}+\left(\sqrt{15}\right)^{2}}{5}
Multiply 3 and 5 to get 15.
\frac{30+15\sqrt{3}+2\sqrt{5}\sqrt{3}\sqrt{5}+\left(\sqrt{15}\right)^{2}}{5}
Factor 15=5\times 3. Rewrite the square root of the product \sqrt{5\times 3} as the product of square roots \sqrt{5}\sqrt{3}.
\frac{30+15\sqrt{3}+2\times 5\sqrt{3}+\left(\sqrt{15}\right)^{2}}{5}
Multiply \sqrt{5} and \sqrt{5} to get 5.
\frac{30+15\sqrt{3}+10\sqrt{3}+\left(\sqrt{15}\right)^{2}}{5}
Multiply 2 and 5 to get 10.
\frac{30+25\sqrt{3}+\left(\sqrt{15}\right)^{2}}{5}
Combine 15\sqrt{3} and 10\sqrt{3} to get 25\sqrt{3}.
\frac{30+25\sqrt{3}+15}{5}
The square of \sqrt{15} is 15.
\frac{45+25\sqrt{3}}{5}
Add 30 and 15 to get 45.
9+5\sqrt{3}
Divide each term of 45+25\sqrt{3} by 5 to get 9+5\sqrt{3}.