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\frac{3\sqrt{5}\sqrt{7}}{\left(\sqrt{7}\right)^{2}}+2\sqrt{2}
Rationalize the denominator of \frac{3\sqrt{5}}{\sqrt{7}} by multiplying numerator and denominator by \sqrt{7}.
\frac{3\sqrt{5}\sqrt{7}}{7}+2\sqrt{2}
The square of \sqrt{7} is 7.
\frac{3\sqrt{35}}{7}+2\sqrt{2}
To multiply \sqrt{5} and \sqrt{7}, multiply the numbers under the square root.
\frac{3\sqrt{35}}{7}+\frac{7\times 2\sqrt{2}}{7}
To add or subtract expressions, expand them to make their denominators the same. Multiply 2\sqrt{2} times \frac{7}{7}.
\frac{3\sqrt{35}+7\times 2\sqrt{2}}{7}
Since \frac{3\sqrt{35}}{7} and \frac{7\times 2\sqrt{2}}{7} have the same denominator, add them by adding their numerators.
\frac{3\sqrt{35}+14\sqrt{2}}{7}
Do the multiplications in 3\sqrt{35}+7\times 2\sqrt{2}.