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\frac{3\times 2}{8\left(1\times 2+1\right)}+\frac{1\times 4+1}{4}
Divide \frac{3}{8} by \frac{1\times 2+1}{2} by multiplying \frac{3}{8} by the reciprocal of \frac{1\times 2+1}{2}.
\frac{3}{4\left(1+2\right)}+\frac{1\times 4+1}{4}
Cancel out 2 in both numerator and denominator.
\frac{3}{4\times 3}+\frac{1\times 4+1}{4}
Add 1 and 2 to get 3.
\frac{3}{12}+\frac{1\times 4+1}{4}
Multiply 4 and 3 to get 12.
\frac{1}{4}+\frac{1\times 4+1}{4}
Reduce the fraction \frac{3}{12} to lowest terms by extracting and canceling out 3.
\frac{1}{4}+\frac{4+1}{4}
Multiply 1 and 4 to get 4.
\frac{1}{4}+\frac{5}{4}
Add 4 and 1 to get 5.
\frac{1+5}{4}
Since \frac{1}{4} and \frac{5}{4} have the same denominator, add them by adding their numerators.
\frac{6}{4}
Add 1 and 5 to get 6.
\frac{3}{2}
Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.