Solve 3/4+-2/3left(-2)(-3right)-4+3

$$\frac{ 3 }{ 4 } +- \frac{ 2 }{ 3 } \left( -2)(-3 \right) -4+3$$

Evaluate

$$-\frac{17}{4}=-4.25$$

Solution Steps

Express -\frac{2}{3}\left(-2\right) as a single fraction.

$$\frac{3}{4}+\frac{-2\left(-2\right)}{3}\left(-3\right)-4+3$$

Multiply -2 and -2 to get 4.

$$\frac{3}{4}+\frac{4}{3}\left(-3\right)-4+3$$

Express \frac{4}{3}\left(-3\right) as a single fraction.

$$\frac{3}{4}+\frac{4\left(-3\right)}{3}-4+3$$

Multiply 4 and -3 to get -12.

$$\frac{3}{4}+\frac{-12}{3}-4+3$$

Divide -12 by 3 to get -4.

$$\frac{3}{4}-4-4+3$$

Convert 4 to fraction \frac{16}{4}.

$$\frac{3}{4}-\frac{16}{4}-4+3$$

Since \frac{3}{4} and \frac{16}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-16}{4}-4+3$$

Subtract 16 from 3 to get -13.

$$-\frac{13}{4}-4+3$$

Convert 4 to fraction \frac{16}{4}.

$$-\frac{13}{4}-\frac{16}{4}+3$$

Since -\frac{13}{4} and \frac{16}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-13-16}{4}+3$$

Subtract 16 from -13 to get -29.

$$-\frac{29}{4}+3$$

Convert 3 to fraction \frac{12}{4}.

$$-\frac{29}{4}+\frac{12}{4}$$

Since -\frac{29}{4} and \frac{12}{4} have the same denominator, add them by adding their numerators.

$$\frac{-29+12}{4}$$

Add -29 and 12 to get -17.

$$-\frac{17}{4}$$

Factor

$$-\frac{17}{4} = -4\frac{1}{4} = -4.25$$