Solve 3/4+3/4-3/43/4-frac{3}{4}+frac{frac{3}{4}}{frac{3}{4}}

$$\frac{ 3 }{ 4 } + \frac{ 3 }{ 4 } - \frac{ 3 }{ 4 } \frac{ 3 }{ 4 } - \frac{ 3 }{ 4 } + \frac{ \frac{ 3 }{ 4 } }{ \frac{ 3 }{ 4 } }$$

Evaluate

$$\frac{19}{16}=1.1875$$

Solution Steps

Divide \frac{3}{4} by \frac{3}{4} to get 1.

$$\frac{3}{4}+\frac{3}{4}-\frac{3}{4}\times \frac{3}{4}-\frac{3}{4}+1$$

Since \frac{3}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$\frac{3+3}{4}-\frac{3}{4}\times \frac{3}{4}-\frac{3}{4}+1$$

Add 3 and 3 to get 6.

$$\frac{6}{4}-\frac{3}{4}\times \frac{3}{4}-\frac{3}{4}+1$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{3}{2}-\frac{3}{4}\times \frac{3}{4}-\frac{3}{4}+1$$

Multiply \frac{3}{4} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3}{2}-\frac{3\times 3}{4\times 4}-\frac{3}{4}+1$$

Do the multiplications in the fraction \frac{3\times 3}{4\times 4}.

$$\frac{3}{2}-\frac{9}{16}-\frac{3}{4}+1$$

Least common multiple of 2 and 16 is 16. Convert \frac{3}{2} and \frac{9}{16} to fractions with denominator 16.

$$\frac{24}{16}-\frac{9}{16}-\frac{3}{4}+1$$

Since \frac{24}{16} and \frac{9}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{24-9}{16}-\frac{3}{4}+1$$

Subtract 9 from 24 to get 15.

$$\frac{15}{16}-\frac{3}{4}+1$$

Least common multiple of 16 and 4 is 16. Convert \frac{15}{16} and \frac{3}{4} to fractions with denominator 16.

$$\frac{15}{16}-\frac{12}{16}+1$$

Since \frac{15}{16} and \frac{12}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{15-12}{16}+1$$

Subtract 12 from 15 to get 3.

$$\frac{3}{16}+1$$

Convert 1 to fraction \frac{16}{16}.

$$\frac{3}{16}+\frac{16}{16}$$

Since \frac{3}{16} and \frac{16}{16} have the same denominator, add them by adding their numerators.

$$\frac{3+16}{16}$$

Add 3 and 16 to get 19.

$$\frac{19}{16}$$

Factor

$$\frac{19}{2 ^ {4}} = 1\frac{3}{16} = 1.1875$$