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5\times 3=3\left(y+3\right)
Variable y cannot be equal to -3 since division by zero is not defined. Multiply both sides of the equation by 5\left(y+3\right), the least common multiple of 3+y^{1},5.
15=3\left(y+3\right)
Multiply 5 and 3 to get 15.
15=3y+9
Use the distributive property to multiply 3 by y+3.
3y+9=15
Swap sides so that all variable terms are on the left hand side.
3y=15-9
Subtract 9 from both sides.
3y=6
Subtract 9 from 15 to get 6.
y=\frac{6}{3}
Divide both sides by 3.
y=2
Divide 6 by 3 to get 2.