Solve for x
x\geq \frac{16}{3}
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\frac{3}{2}x\geq 8
Add 8 to both sides. Anything plus zero gives itself.
x\geq 8\times \frac{2}{3}
Multiply both sides by \frac{2}{3}, the reciprocal of \frac{3}{2}. Since \frac{3}{2} is positive, the inequality direction remains the same.
x\geq \frac{8\times 2}{3}
Express 8\times \frac{2}{3} as a single fraction.
x\geq \frac{16}{3}
Multiply 8 and 2 to get 16.
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