Solve 3/2-1/5*5-1/10*3/4-frac{6}{5}

$$\frac{ 3 }{ 2 } - \frac{ 1 }{ 5 } \times 5- \frac{ 1 }{ 10 } \times \frac{ 3 }{ 4 } - \frac{ 6 }{ 5 }$$

Evaluate

$$-\frac{31}{40}=-0.775$$

Solution Steps

Cancel out 5 and 5.

$$\frac{3}{2}-1-\frac{1}{10}\times \frac{3}{4}-\frac{6}{5}$$

Convert 1 to fraction \frac{2}{2}.

$$\frac{3}{2}-\frac{2}{2}-\frac{1}{10}\times \frac{3}{4}-\frac{6}{5}$$

Since \frac{3}{2} and \frac{2}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-2}{2}-\frac{1}{10}\times \frac{3}{4}-\frac{6}{5}$$

Subtract 2 from 3 to get 1.

$$\frac{1}{2}-\frac{1}{10}\times \frac{3}{4}-\frac{6}{5}$$

Multiply \frac{1}{10} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1}{2}-\frac{1\times 3}{10\times 4}-\frac{6}{5}$$

Do the multiplications in the fraction \frac{1\times 3}{10\times 4}.

$$\frac{1}{2}-\frac{3}{40}-\frac{6}{5}$$

Least common multiple of 2 and 40 is 40. Convert \frac{1}{2} and \frac{3}{40} to fractions with denominator 40.

$$\frac{20}{40}-\frac{3}{40}-\frac{6}{5}$$

Since \frac{20}{40} and \frac{3}{40} have the same denominator, subtract them by subtracting their numerators.

$$\frac{20-3}{40}-\frac{6}{5}$$

Subtract 3 from 20 to get 17.

$$\frac{17}{40}-\frac{6}{5}$$

Least common multiple of 40 and 5 is 40. Convert \frac{17}{40} and \frac{6}{5} to fractions with denominator 40.

$$\frac{17}{40}-\frac{48}{40}$$

Since \frac{17}{40} and \frac{48}{40} have the same denominator, subtract them by subtracting their numerators.

$$\frac{17-48}{40}$$

Subtract 48 from 17 to get -31.

$$-\frac{31}{40}$$

Factor

$$-\frac{31}{40} = -0.775$$