Solve for x
x<\frac{15}{8}
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Algebra
5 problems similar to:
\frac{ 3 }{ 2 } \left( \frac{ 1 }{ 2 } -x \right) > \frac{ x }{ 2 } -3
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3\left(\frac{1}{2}-x\right)>x-6
Multiply both sides of the equation by 2. Since 2 is positive, the inequality direction remains the same.
3\times \frac{1}{2}-3x>x-6
Use the distributive property to multiply 3 by \frac{1}{2}-x.
\frac{3}{2}-3x>x-6
Multiply 3 and \frac{1}{2} to get \frac{3}{2}.
\frac{3}{2}-3x-x>-6
Subtract x from both sides.
\frac{3}{2}-4x>-6
Combine -3x and -x to get -4x.
-4x>-6-\frac{3}{2}
Subtract \frac{3}{2} from both sides.
-4x>-\frac{12}{2}-\frac{3}{2}
Convert -6 to fraction -\frac{12}{2}.
-4x>\frac{-12-3}{2}
Since -\frac{12}{2} and \frac{3}{2} have the same denominator, subtract them by subtracting their numerators.
-4x>-\frac{15}{2}
Subtract 3 from -12 to get -15.
x<\frac{-\frac{15}{2}}{-4}
Divide both sides by -4. Since -4 is negative, the inequality direction is changed.
x<\frac{-15}{2\left(-4\right)}
Express \frac{-\frac{15}{2}}{-4} as a single fraction.
x<\frac{-15}{-8}
Multiply 2 and -4 to get -8.
x<\frac{15}{8}
Fraction \frac{-15}{-8} can be simplified to \frac{15}{8} by removing the negative sign from both the numerator and the denominator.
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Limits
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