Solve 3/19+2-sqrt{19-3}

$$\frac{ 3 }{ 19+2 } - \sqrt{ 19-3 }$$

Evaluate

$$-\frac{27}{7}\approx -3.857142857$$

Solution Steps

Add 19 and 2 to get 21.

$$\frac{3}{21}-\sqrt{19-3}$$

Reduce the fraction \frac{3}{21} to lowest terms by extracting and canceling out 3.

$$\frac{1}{7}-\sqrt{19-3}$$

Subtract 3 from 19 to get 16.

$$\frac{1}{7}-\sqrt{16}$$

Calculate the square root of 16 and get 4.

$$\frac{1}{7}-4$$

Convert 4 to fraction \frac{28}{7}.

$$\frac{1}{7}-\frac{28}{7}$$

Since \frac{1}{7} and \frac{28}{7} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-28}{7}$$

Subtract 28 from 1 to get -27.

$$-\frac{27}{7}$$

Factor

$$-\frac{27}{7} = -3\frac{6}{7} = -3.857142857142857$$