Solve 3/-x-7-5/7x+7

$$\frac{ 3 }{ -x-7 } \frac{ -5 }{ 7x+7 }$$

Evaluate

$$\frac{15}{7\left(x+1\right)\left(x+7\right)}$$

Solution Steps

Multiply \frac{3}{-x-7} times \frac{-5}{7x+7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\left(-5\right)}{\left(-x-7\right)\left(7x+7\right)}$$

Multiply 3 and -5 to get -15.

$$\frac{-15}{\left(-x-7\right)\left(7x+7\right)}$$

Apply the distributive property by multiplying each term of -x-7 by each term of 7x+7.

$$\frac{-15}{-7x^{2}-7x-49x-49}$$

Combine -7x and -49x to get -56x.

$$\frac{-15}{-7x^{2}-56x-49}$$

Differentiate w.r.t. x

$$\frac{30\left(-x-4\right)}{7\left(\left(x+1\right)\left(x+7\right)\right)^{2}}$$