Solve 3/x^2=2x+y

$$\frac{ 3 }{ { x }^{ 2 } } = 2x+y$$

Solve for y

$$y=-2x+\frac{3}{x^{2}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by x^{2}.

$$3=2xx^{2}+x^{2}y$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$3=2x^{3}+x^{2}y$$

Swap sides so that all variable terms are on the left hand side.

$$2x^{3}+x^{2}y=3$$

Subtract 2x^{3} from both sides.

$$x^{2}y=3-2x^{3}$$

Divide both sides by x^{2}.

$$\frac{x^{2}y}{x^{2}}=\frac{3-2x^{3}}{x^{2}}$$

Dividing by x^{2} undoes the multiplication by x^{2}.

$$y=\frac{3-2x^{3}}{x^{2}}$$

Divide -2x^{3}+3 by x^{2}.

$$y=-2x+\frac{3}{x^{2}}$$