Solve 3!/3!(10-3)!

$$\frac{ 3 ! }{ 3 ! (10-3) ! }$$

Evaluate

$$\frac{1}{5040}\approx 0.000198413$$

Solution Steps

The factorial of 3 is 6.

$$\frac{6}{3!\left(10-3\right)!}$$

The factorial of 3 is 6.

$$\frac{6}{6\left(10-3\right)!}$$

Subtract 3 from 10 to get 7.

$$\frac{6}{6\times 7!}$$

The factorial of 7 is 5040.

$$\frac{6}{6\times 5040}$$

Multiply 6 and 5040 to get 30240.

$$\frac{6}{30240}$$

Reduce the fraction \frac{6}{30240} to lowest terms by extracting and canceling out 6.

$$\frac{1}{5040}$$

Factor

$$\frac{1}{2 ^ {4} \cdot 3 ^ {2} \cdot 5 \cdot 7} = 0.0001984126984126984$$