Solve 2y/3geqydiv4-3

$$\frac{ 2y }{ 3 } \geq y \div 4-3$$

Solve for y

$$y\geq -\frac{36}{5}$$

Solution Steps

Multiply both sides of the equation by 12, the least common multiple of 3,4. Since 12 is positive, the inequality direction remains the same.

$$4\times 2y\geq 3y-36$$

Multiply 4 and 2 to get 8.

$$8y\geq 3y-36$$

Subtract 3y from both sides.

$$8y-3y\geq -36$$

Combine 8y and -3y to get 5y.

$$5y\geq -36$$

Divide both sides by 5. Since 5 is positive, the inequality direction remains the same.

$$y\geq -\frac{36}{5}$$