Solve 2xy/x^2-y^2x^2-y^2/16{x^3y}

$$\frac{ 2xy }{ { x }^{ 2 } - { y }^{ 2 } } \frac{ { x }^{ 2 } - { y }^{ 2 } }{ 16 { x }^{ 3 } y }$$

Evaluate

$$\frac{1}{8x^{2}}$$

Short Solution Steps

Multiply \frac{2xy}{x^{2}-y^{2}} times \frac{x^{2}-y^{2}}{16x^{3}y} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2xy\left(x^{2}-y^{2}\right)}{\left(x^{2}-y^{2}\right)\times 16x^{3}y}$$

Cancel out 2xy\left(x^{2}-y^{2}\right) in both numerator and denominator.

$$\frac{1}{8x^{2}}$$

Expand

$$\frac{1}{8x^{2}}$$

Short Solution Steps

Multiply \frac{2xy}{x^{2}-y^{2}} times \frac{x^{2}-y^{2}}{16x^{3}y} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2xy\left(x^{2}-y^{2}\right)}{\left(x^{2}-y^{2}\right)\times 16x^{3}y}$$

Cancel out 2xy\left(x^{2}-y^{2}\right) in both numerator and denominator.

$$\frac{1}{8x^{2}}$$