Solve 2x-3/left(-x^2+3x+4right)^2=0

$$\frac{ 2x-3 }{ { \left(- { x }^{ 2 } +3x+4 \right) }^{ 2 } } =0$$

Solve for x

$$x = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

Steps for Solving Linear Equation

Square -x^{2}+3x+4.

$$\frac{2x-3}{9x^{2}+8\left(-x^{2}\right)+6x\left(-x^{2}\right)+24x+\left(-x^{2}\right)^{2}+16}=0$$

Calculate -x^{2} to the power of 2 and get \left(x^{2}\right)^{2}.

$$\frac{2x-3}{9x^{2}+8\left(-x^{2}\right)+6x\left(-x^{2}\right)+24x+\left(x^{2}\right)^{2}+16}=0$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$\frac{2x-3}{9x^{2}+8\left(-x^{2}\right)+6x\left(-x^{2}\right)+24x+x^{4}+16}=0$$

Variable x cannot be equal to any of the values -1,4 since division by zero is not defined. Multiply both sides of the equation by \left(x-4\right)^{2}\left(x+1\right)^{2}.

$$2x-3=0$$

Add 3 to both sides. Anything plus zero gives itself.

$$2x=3$$

Divide both sides by 2.

$$x=\frac{3}{2}$$