Solve for x
x=2
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\left(x+1\right)\left(2x+8\right)=\left(x+2\right)\left(2x+5\right)
Variable x cannot be equal to any of the values -2,-1 since division by zero is not defined. Multiply both sides of the equation by \left(x+1\right)\left(x+2\right), the least common multiple of x+2,x+1.
2x^{2}+10x+8=\left(x+2\right)\left(2x+5\right)
Use the distributive property to multiply x+1 by 2x+8 and combine like terms.
2x^{2}+10x+8=2x^{2}+9x+10
Use the distributive property to multiply x+2 by 2x+5 and combine like terms.
2x^{2}+10x+8-2x^{2}=9x+10
Subtract 2x^{2} from both sides.
10x+8=9x+10
Combine 2x^{2} and -2x^{2} to get 0.
10x+8-9x=10
Subtract 9x from both sides.
x+8=10
Combine 10x and -9x to get x.
x=10-8
Subtract 8 from both sides.
x=2
Subtract 8 from 10 to get 2.
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