Solve 2x/x+3-6x/2

$$\frac{ 2x }{ x+3 } - \frac{ 6x }{ 2 }$$

Evaluate

$$-\frac{x\left(3x+7\right)}{x+3}$$

Short Solution Steps

Divide 6x by 2 to get 3x.

$$\frac{2x}{x+3}-3x$$

To add or subtract expressions, expand them to make their denominators the same. Multiply -3x times \frac{x+3}{x+3}.

$$\frac{2x}{x+3}+\frac{-3x\left(x+3\right)}{x+3}$$

Since \frac{2x}{x+3} and \frac{-3x\left(x+3\right)}{x+3} have the same denominator, add them by adding their numerators.

$$\frac{2x-3x\left(x+3\right)}{x+3}$$

Do the multiplications in 2x-3x\left(x+3\right).

$$\frac{2x-3x^{2}-9x}{x+3}$$

Combine like terms in 2x-3x^{2}-9x.

$$\frac{-7x-3x^{2}}{x+3}$$

Factor

$$-\frac{x\left(3x+7\right)}{x+3}$$