Solve 2x/3+2=3x/(2+6)(5)

$$\frac{ 2x }{ 3+2 } = \frac{ 3x }{ (2+6)(5) }$$

Solve for x

$$x=0$$

Steps for Solving Linear Equation

Add 3 and 2 to get 5.

$$\frac{2x}{5}=\frac{3x}{\left(2+6\right)\times 5}$$

Add 2 and 6 to get 8.

$$\frac{2x}{5}=\frac{3x}{8\times 5}$$

Multiply 8 and 5 to get 40.

$$\frac{2x}{5}=\frac{3x}{40}$$

Subtract \frac{3x}{40} from both sides.

$$\frac{2x}{5}-\frac{3x}{40}=0$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 5 and 40 is 40. Multiply \frac{2x}{5} times \frac{8}{8}.

$$\frac{8\times 2x}{40}-\frac{3x}{40}=0$$

Since \frac{8\times 2x}{40} and \frac{3x}{40} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8\times 2x-3x}{40}=0$$

Do the multiplications in 8\times 2x-3x.

$$\frac{16x-3x}{40}=0$$

Combine like terms in 16x-3x.

$$\frac{13x}{40}=0$$

Multiply both sides by 40. Anything times zero gives zero.

$$13x=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since 13 is not equal to 0, x must be equal to 0.

$$x=0$$