Solve for x
x=\frac{11}{43}\approx 0.255813953
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Linear Equation
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\frac{ 29 }{ 43 } -(x+ \frac{ 13 }{ 43 } )= \frac{ 5 }{ 43 }
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\frac{29}{43}-x-\frac{13}{43}=\frac{5}{43}
To find the opposite of x+\frac{13}{43}, find the opposite of each term.
\frac{29-13}{43}-x=\frac{5}{43}
Since \frac{29}{43} and \frac{13}{43} have the same denominator, subtract them by subtracting their numerators.
\frac{16}{43}-x=\frac{5}{43}
Subtract 13 from 29 to get 16.
-x=\frac{5}{43}-\frac{16}{43}
Subtract \frac{16}{43} from both sides.
-x=\frac{5-16}{43}
Since \frac{5}{43} and \frac{16}{43} have the same denominator, subtract them by subtracting their numerators.
-x=-\frac{11}{43}
Subtract 16 from 5 to get -11.
x=\frac{11}{43}
Multiply both sides by -1.
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