Solve 28/99-24/990-03/99

$$\frac{ 28 }{ 99 } - \frac{ 24 }{ 990 } - \frac{ 03 }{ 99 }$$

Evaluate

$$\frac{128}{495}\approx 0.258585859$$

Solution Steps

Reduce the fraction \frac{24}{990} to lowest terms by extracting and canceling out 6.

$$\frac{28}{99}-\frac{4}{165}-\frac{0\times 3}{99}$$

Least common multiple of 99 and 165 is 495. Convert \frac{28}{99} and \frac{4}{165} to fractions with denominator 495.

$$\frac{140}{495}-\frac{12}{495}-\frac{0\times 3}{99}$$

Since \frac{140}{495} and \frac{12}{495} have the same denominator, subtract them by subtracting their numerators.

$$\frac{140-12}{495}-\frac{0\times 3}{99}$$

Subtract 12 from 140 to get 128.

$$\frac{128}{495}-\frac{0\times 3}{99}$$

Multiply 0 and 3 to get 0.

$$\frac{128}{495}-\frac{0}{99}$$

Zero divided by any non-zero number gives zero.

$$\frac{128}{495}+0$$

Add \frac{128}{495} and 0 to get \frac{128}{495}.

$$\frac{128}{495}$$

Factor

$$\frac{2 ^ {7}}{3 ^ {2} \cdot 5 \cdot 11} = 0.2585858585858586$$