Solve 28/5(5/7*3/2+1/14)=

$$\frac{ 28 }{ 5 } ( \frac{ 5 }{ 7 } \times \frac { 3 } { 2 } + \frac{ 1 }{ 14 } )=$$

Evaluate

$$\frac{32}{5}=6.4$$

Solution Steps

Multiply \frac{5}{7} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{28}{5}\left(\frac{5\times 3}{7\times 2}+\frac{1}{14}\right)$$

Do the multiplications in the fraction \frac{5\times 3}{7\times 2}.

$$\frac{28}{5}\left(\frac{15}{14}+\frac{1}{14}\right)$$

Since \frac{15}{14} and \frac{1}{14} have the same denominator, add them by adding their numerators.

$$\frac{28}{5}\times \frac{15+1}{14}$$

Add 15 and 1 to get 16.

$$\frac{28}{5}\times \frac{16}{14}$$

Reduce the fraction \frac{16}{14} to lowest terms by extracting and canceling out 2.

$$\frac{28}{5}\times \frac{8}{7}$$

Multiply \frac{28}{5} times \frac{8}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{28\times 8}{5\times 7}$$

Do the multiplications in the fraction \frac{28\times 8}{5\times 7}.

$$\frac{224}{35}$$

Reduce the fraction \frac{224}{35} to lowest terms by extracting and canceling out 7.

$$\frac{32}{5}$$

Factor

$$\frac{2 ^ {5}}{5} = 6\frac{2}{5} = 6.4$$