Solve 27/414/9+14/412/7

$$\frac{ 27 }{ 41 } \frac{ 4 }{ 9 } + \frac{ 14 }{ 41 } \frac{ 2 }{ 7 }$$

Evaluate

$$\frac{16}{41}\approx 0.390243902$$

Solution Steps

Multiply \frac{27}{41} times \frac{4}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{27\times 4}{41\times 9}+\frac{14}{41}\times \frac{2}{7}$$

Do the multiplications in the fraction \frac{27\times 4}{41\times 9}.

$$\frac{108}{369}+\frac{14}{41}\times \frac{2}{7}$$

Reduce the fraction \frac{108}{369} to lowest terms by extracting and canceling out 9.

$$\frac{12}{41}+\frac{14}{41}\times \frac{2}{7}$$

Multiply \frac{14}{41} times \frac{2}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{12}{41}+\frac{14\times 2}{41\times 7}$$

Do the multiplications in the fraction \frac{14\times 2}{41\times 7}.

$$\frac{12}{41}+\frac{28}{287}$$

Reduce the fraction \frac{28}{287} to lowest terms by extracting and canceling out 7.

$$\frac{12}{41}+\frac{4}{41}$$

Since \frac{12}{41} and \frac{4}{41} have the same denominator, add them by adding their numerators.

$$\frac{12+4}{41}$$

Add 12 and 4 to get 16.

$$\frac{16}{41}$$

Factor

$$\frac{2 ^ {4}}{41} = 0.3902439024390244$$