Solve 25/6+4/9*2/3^2=

$$\frac{ 25 }{ 6 } + \frac{ 4 }{ 9 } \times \frac{ 2 }{ { 3 }^{ 2 } } =$$

Evaluate

$$\frac{691}{162}\approx 4.265432099$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$\frac{25}{6}+\frac{4}{9}\times \frac{2}{9}$$

Multiply \frac{4}{9} times \frac{2}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{25}{6}+\frac{4\times 2}{9\times 9}$$

Do the multiplications in the fraction \frac{4\times 2}{9\times 9}.

$$\frac{25}{6}+\frac{8}{81}$$

Least common multiple of 6 and 81 is 162. Convert \frac{25}{6} and \frac{8}{81} to fractions with denominator 162.

$$\frac{675}{162}+\frac{16}{162}$$

Since \frac{675}{162} and \frac{16}{162} have the same denominator, add them by adding their numerators.

$$\frac{675+16}{162}$$

Add 675 and 16 to get 691.

$$\frac{691}{162}$$

Factor

$$\frac{691}{2 \cdot 3 ^ {4}} = 4\frac{43}{162} = 4.265432098765432$$