Solve 25/36+41/12

$$\frac{ 25 }{ 36 } + \frac{ 41 }{ 12 }$$

Evaluate

$$\frac{37}{9}\approx 4.111111111$$

Solution Steps

Least common multiple of 36 and 12 is 36. Convert \frac{25}{36} and \frac{41}{12} to fractions with denominator 36.

$$\frac{25}{36}+\frac{123}{36}$$

Since \frac{25}{36} and \frac{123}{36} have the same denominator, add them by adding their numerators.

$$\frac{25+123}{36}$$

Add 25 and 123 to get 148.

$$\frac{148}{36}$$

Reduce the fraction \frac{148}{36} to lowest terms by extracting and canceling out 4.

$$\frac{37}{9}$$

Factor

$$\frac{37}{3 ^ {2}} = 4\frac{1}{9} = 4.111111111111111$$