Solve 25/21+8/7+4/3

$$\frac{ 25 }{ 21 } + \frac{ 8 }{ 7 } + \frac{ 4 }{ 3 }$$

Evaluate

$$\frac{11}{3}\approx 3.666666667$$

Solution Steps

Least common multiple of 21 and 7 is 21. Convert \frac{25}{21} and \frac{8}{7} to fractions with denominator 21.

$$\frac{25}{21}+\frac{24}{21}+\frac{4}{3}$$

Since \frac{25}{21} and \frac{24}{21} have the same denominator, add them by adding their numerators.

$$\frac{25+24}{21}+\frac{4}{3}$$

Add 25 and 24 to get 49.

$$\frac{49}{21}+\frac{4}{3}$$

Reduce the fraction \frac{49}{21} to lowest terms by extracting and canceling out 7.

$$\frac{7}{3}+\frac{4}{3}$$

Since \frac{7}{3} and \frac{4}{3} have the same denominator, add them by adding their numerators.

$$\frac{7+4}{3}$$

Add 7 and 4 to get 11.

$$\frac{11}{3}$$

Factor

$$\frac{11}{3} = 3\frac{2}{3} = 3.6666666666666665$$