Solve 247/10+108/11+148/803

$$\frac{ 247 }{ 10 } + \frac{ 108 }{ 11 } + \frac{ 148 }{ 803 }$$

Evaluate

$$\frac{278661}{8030}\approx 34.70249066$$

Solution Steps

Least common multiple of 10 and 11 is 110. Convert \frac{247}{10} and \frac{108}{11} to fractions with denominator 110.

$$\frac{2717}{110}+\frac{1080}{110}+\frac{148}{803}$$

Since \frac{2717}{110} and \frac{1080}{110} have the same denominator, add them by adding their numerators.

$$\frac{2717+1080}{110}+\frac{148}{803}$$

Add 2717 and 1080 to get 3797.

$$\frac{3797}{110}+\frac{148}{803}$$

Least common multiple of 110 and 803 is 8030. Convert \frac{3797}{110} and \frac{148}{803} to fractions with denominator 8030.

$$\frac{277181}{8030}+\frac{1480}{8030}$$

Since \frac{277181}{8030} and \frac{1480}{8030} have the same denominator, add them by adding their numerators.

$$\frac{277181+1480}{8030}$$

Add 277181 and 1480 to get 278661.

$$\frac{278661}{8030}$$

Factor

$$\frac{3 \cdot 29 \cdot 3203}{2 \cdot 5 \cdot 11 \cdot 73} = 34\frac{5641}{8030} = 34.70249066002491$$